Random numbers, how to? |
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Random numbers, how to? |
Jul 21 2005, 05:25 PM
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#1
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Member ![]() ![]() ![]() Posts: 166 OS: XP |
ive defined an integer dim X as integer and the i did X=RND() this works but it only goes between 1 and 0, how do i change so it will pick a number between 15 and 35 (inclusive)? thanks ben hey dw bout it i found a solution on msdn.microsoft.com if ne1s interested the solution is CInt(Int((upperbound - lowerbound + 1) * Rnd() + lowerbound)) upperbound means highest number and lowerbound means lowest This post has been edited by BTPH: Jul 21 2005, 05:31 PM |
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Jul 22 2005, 03:13 AM
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#2
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Member ![]() ![]() Posts: 48 OS: win 98, xp pro and 2000 server |
easiest and simple way to do!!!!
Random is a class in .net. they are not real random they are only algorithm so that makes sense you can creat your own random algorithm that generates random numbers class abc { static void Main() { Random random=new Random(1 )// 1 is seed number pseudo random number sequence you can change it whatever you like while(true)//you have to check the loop there are too many ways and it is your job { int ranNum=random.Next(100);//instead int you can change the type of variable ranNum like double it depends what is the max number you want Console.WriteLine(ranNum);//prints random numbers put break point in this line that you can watch it slowly with pressing F5 } }} another way the following code returns a random number between min and max in this example random numbers are limited between minimum and maximum private int RandomNumber(int min, int max) { Random ran=new Random(); return ran.Next(min,max); } takeCare BuRnEr |
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