|The One I Solved Myself|
-------------------------

Problem: Have the user input a 4-digit integer value. Have your program convert this integer into a character array without using the itoa function.

#include <iostream>
#include <string>
using namespace std;

int main()
{
	int nNum, nT, nH, nTen, nO, i;
	char arcNum[4];
	cout<<"Please enter a four-digit number"<<endl;
	cin>>nNum;
	nT=nNum/1000;
	arcNum[0]=nT+'0';

	nH=(nNum/100)-(nT*10);
	arcNum[1]=nH+'0';

	nTen=(nNum/10)-(nT*100)-(nH*10);
	arcNum[2]=nTen+'0';

	nO=nNum-(nT*1000)-(nH*100)-(nTen*10);
	arcNum[3]=nO+'0';
	for(i=0; i<4; i++)
	{
	cout<<arcNum[i];
	}
	cout<<endl;
}

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|The Ones I Need Solved|
-----------------------

Problem 1: Have the user input a 4-digit character array or string. Have your program convert this string into an integer value without using the atoi function.

PS: my teacher said it would include subtracting '0' rather than adding it or something...

Problem 2: l)	Have the user guess at random number. Have the computer tell the user either “Higher” or “Lower” until correct. The program will show the total number of guesses. Also, if the 
                user is a moron, tell them so. For example, assume the correct number is 12. If the user inputs 7 and your program informs the user “higher”, if at any later time the user inputs a number of 7 
                or lower, the program is permitted to call the user a “moron”.








PS: Please try to code at a similar level like above
PSSS: I appriciate it, thanks :)