Posted 21 December 2007 - 12:20 PM
Posted 21 December 2007 - 03:59 PM
consider a combo of Intel Q6600 (FSB 1066), Micron D9GKX RAM DDR2-800, and Gigabyte P35-DS3R motherboard
Intel Q6600 is running at 2.40GHz or 2400+-MHz. FSB 1066 is the rated FSB (formula: divided by 4) for respective processor, hence, 1066/4 = 266.5fsb (in this case we consider 266 fsb). To make it rated at 2400MHz, the formula is (speed / fsb) which means 2400/266 = 9.02 (we take it as 9). The easy words is 266fsb need 9x (or 9-multiplier) to make it 2400MHz (2.4GHz) rated speed.
Another example is E6750 (2.66GHz) (FSB1333)
1. FSB 1333 divided by 4 = 333.25 (we take it as 333fsb) *remember, always divide FSB by 4
2. we know the speed of E6750 is 2.66GHz = 2667MHz, so, 2667MHz / 333 = 8.01 (we ttake it as 8x or 8-multi)
3. so, 333fsb times 8-multi we get 2.67GHz..
DDR2-800 *formula = always divided by 2. means DDR2-800 runs at 400MHz.
DDR2-667 = runs at 333MHz
to make processor fsb and RAM speed ratio is equal to 1:1 then consider this
Type: fsb : RAM
Ratio: 1 : 1
Speed: 333 : 333
FSB: 1333 667
Type: fsb : RAM
Ratio: 5 : 8
Speed: 266 : 400
FSB: 1066 : 800
the colored ones that's important to think of fsb:ram ratio
and both processor and RAM speed can be set manually in BIOS (at motherboard)
has BIOS to set up those fsb, multiplier and RAM speed ratio manually
-you need to have first-hand experience to understand it deeply-means you have to do it yourself at your own risk-
-always reset CMOS if you setting gone wrong-
Edited by fenzodahl512, 21 December 2007 - 04:00 PM.
0 user(s) are reading this topic
0 members, 0 guests, 0 anonymous users