[ali.B]

hello,

i started learning c++ few weeks ago, i am writting a program which will read 3 numbers and displays the smallest value

is this wrong:

if (num1 < num2) && (num1 < num3)

because that's where i am getting the error "expression syntax"

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I believe it should be:

if((num1 < num2) && (num1 < num3))
{
...
}

You need open and closing parentheses around the if statements, following the model:

if(condition)
{
...
}

Hope that helps

[mpascal]

I believe it should be:

if((num1 < num2) && (num1 < num3))
{
...
}

You need open and closing parentheses around the if statements, following the model:

if(condition)
{
...
}

Hope that helps

[ali.B]

Hello,

First thank you for replying

and yes this helped

another question.

i have this code:

cout<< "(A)dd two numbers: "<<endl;
cout<< "(S)ubtract two numbers: "<<endl;
cout<< "(M)ultiply two numbers: "<<endl;
cout<< "(D)ivide two numbers: "<<endl;

How can i make a condition for example if the user selected the first option it will prompt him/her for a action...
in another way : if ( decision ) i want the decision to be selecting one of the above

[mpascal]

If I understand what you're asking, try looking up on the "switch" statement in C++. You want the program to look at multiple conditions and select the correct one?

[ali.B]

let me try to be more clear, i want this menu to appear to the user:

(A)dd two numbers
(S)ubtract two numbers
(M)ultiply two numbers
(D)ivide two numbers

then

Then the program should read two numbers from the user, and display:
Their sum if the user typed a or A as a choice to the above menu
etc..

i am still a newbie with c++ didn't get yet to the switch part..im a practicing...

[Chopin]

I don't like endl;, I like \n

If you want to be really elementary (and rather inefficient) about it, you'd want to declare a char data type to hold the character and use multiple if statements to pass the program onto different functions. The size of the program could be reduced dramatically, but you said you were a beginner and I don't want to confuse you with strange syntaxes

#include <iostream.h> //necessary

float input1, input2, answer //declare calculation vars
char input; //declare input var
float add();
float subtract();
float multiply();//declare funtions. This could be collapsed into one statement
float divide();  //"float add(), subtract(), multiply(), divide();" but not all compilers parse that.

int main()
{
cout << "(A)dd two numbers: \n"; //prompt for input
cout << "(S)ubtract two numbers: \n";
cout << "(M)ultiply two numbers: \n";
cout << "(D)ivide two numbers: \n";
cin >> input;
if ((input == 'a') || (input == 'A')) //call the correct function
add();
if ((input == 's') || (input == 's'))
subtract();
if ((input == 'm') || (input == 'M'))
multiply();
if ((input == 'd') || (input == 'D'))
divide();
cout << "The answer is " << answer << ".\n";
cin.ignore(1,'\n'); //to view result
return 0;
}

<<insert operation functions here>>

Obviously, this doesn't include any error checking. The multiple if statements could also be replaced with a single switch( structure. You should really learn about it; it makes life easier in situations like these

(I took a basic C++ class at my school. They never taught us much C++; it was mostly C If there are any syntax errors, forgive me; probably me forgetting something basic like a semicolon. )

[mpascal]

OK, after the menu the user inputs a letter, and the program determines the operator (addition, subtraction, etc). Then the user inputs two numbers, and then the chosen operator is applied to them?

[ali.B]

exactly!

[mpascal]

OK, so something like this:

#include <iostream>

using namespace std;

int main()
{
int choice, a, b, c;
cout << "1. Add two numbers\n";
cout << "2. Subtract two numbers\n";
cout << "3. Multiply two numbers\n";
cout << "4. Divide two numbers\n\n";
cout << "Enter your selection: ";
cin >> choice;
cout << "Enter first number: ";
cin >> a;
cout << "Enter second number: ";
cin >> b;
if(choice == 1)
c = a + b;
if(choice == 2)
c = a - b;
if(choice == 3)
c = a * b;
if(choice == 4)
c = a / b;
cout << "The result is: " << c << endl;
return 0;
}

That should do it if you want it all in your main function. You can also split it up like Chopin did.

Edited by mpascal, 18 September 2009 - 05:39 PM.

[ali.B]

First thanks a lot.

i have a question

cout << "Enter your selection: ";

why when you enter a number as a selection the program acts that you are selection from the above cout's ? is this just the syntax ?

+ how can i use the if (division by zero) in this code.

Thanks again for your patience and help.

thanks chopin too but i am still not ready to understand your code

[mpascal]

why when you enter a number as a selection the program acts that you are selection from the above cout's ? is this just the syntax ?

Not quite sure I understand. I chose to use numbers as the selection method because it is much easier to handle: you don't have to worry about capital / lowercase. You can still use (A) or (a) for addition, but you would have to change the code slightly.

+ how can i use the if (division by zero) in this code.

A few ways to do this. Since A is always being divided by B, you can assume that B cannot be zero. You can either:

• Use a nested "if" loop in division section such as:

  if(choice == 4)
  {
  if(b == 0)
  cout << "Error: Cannot divide by zero!";
  else
  c = a / b;
  }

• Use a single for loop that is only executed if b is non-zero

  if((choice == 4)  && (b != 0))
  c = a / b;

[ali.B]

I am trying to solve this problem, using the switch annd if's

i must a program that takes a number from a user ( 1,2,3,4...till 100 ) and displays it in french... like 1 is un, 100 is cent.

the problem is i can't make 100 cases of course.

they key for solving is how numbers are written , for example 21 is twenty one ( 20 and 1 ) "vingt un" in french.. but i am having difficulties translating that idea into a code.

[mpascal]

Hi ali.b,

Well, one way you can do it is separate the integer into different parts: first digit and second digit (for numbers 10 - 99). For each digit you have 9 cases:

Digit One:

• dix
• vingt
• trente
• quarante
• cinquante
• soixant
• soixant-dix
• quatrevingt
• quatrevingt-dix

Digit Two:

• un
• deux
• trois
• quatre
• cinq
• six
• sept
• huit
• neuf

(forgive my spelling, I really can't spell in french )

I believe what you should do is split the integer in two and make it the corresponding french digit. For example:

input: 46
digit1: 4
digit2: 6
4 -> quarante
6 -> six
therefore, you are left with "quarante six"

Make any sense? There may be a better way to do this, but this is just what came to mind first.