[sunny441]

Hi there folks,

am pretty weak at the whole concept of probability. I was trying to do some programming and i came across this question in the book.

Approximately 30pc of the calls to an airline reservation phone line results in reservation being made Suppoe the tel operator handles 10 calls.What is the probabilty that none of the 10 calls will generate a reservation

i came with the answer of 7/10. But most people i asked and my friends too thought this was the right. but it cannot be so straight forward... or can it?

hope that some here can help me out..

thanks

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the probability of one call resulting in no reservation is 7/10(70%)

the probability of two calls resulting in no reservation is .7 * .7 = 0.49 or 49%

the probability of 3 calls resulting in no reservation is .7 * .7 * .7 = 0.343 or 34.3%

...

the probability of 10 calls resulting in no reservation is .7 * .7 * .7 * .7 * .7 * .7 * .7 * .7 * .7 * .7 = 0.028 or 2.8%

[bdlt]

the probability of one call resulting in no reservation is 7/10(70%)

the probability of two calls resulting in no reservation is .7 * .7 = 0.49 or 49%

the probability of 3 calls resulting in no reservation is .7 * .7 * .7 = 0.343 or 34.3%

...

the probability of 10 calls resulting in no reservation is .7 * .7 * .7 * .7 * .7 * .7 * .7 * .7 * .7 * .7 = 0.028 or 2.8%