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# Limiting a random number? (C++)

### #1 Throntel Posted 03 February 2006 - 04:14 PM

Throntel

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when I make a random function in a variable like this:

int a = rand();

How do I then limit the rand(); To only randomize betweem numbers from 0-10?
I thought it might be:

int a = rand(0-10);

But it didn't work so I guess that was wrong, also I were wondering how I can make the random funktion include comma (like: 2,34)...

Please respond to this Probably easy for you real geeks out there, I'm currently just a wannabe
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### #2 destin Posted 03 February 2006 - 09:58 PM

destin

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It is really quite simple. What you are trying to do is put an integer argument (0-10 = -10) into the rand() method. It is not overloaded to do that. You obviously were trying 0 through 10, but the '-' operator subtracts.

An easy way to get a random number from 0 to 10 is to simply use the modulus operator:
```int rnd = rand() % 10;
```
Any number % 10 will give you either 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. If you want to set a range, you can use basic math:
```int rand(int min, int max) {
return rand() % (max - min + 1) + min;
}```
Say you want a random number from 5 to 7, you would call it like this: rand(5, 7);
This will mod a random number by 3 (7 - 5 + 1). Now you have a number that is either 0, 1, or 2. Add 5, and you have a number 5, 6, or 7.

As for displaying random number with a comma, you can just append a comma to then end of a random number. For instance, if I wanted to display 5 random numbers:
```for (int i = 0; i < 5; i++) {
cout << rand(0, 10);
if (5 - i > 1) { // we don't want to add an extra comma at the end
cout << ", ";
}
}
```
Hope this helps!

Edited by destin, 04 February 2006 - 11:57 AM.

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### #3 Throntel Posted 04 February 2006 - 05:36 AM

Throntel

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Yeah, it really did.
Thanks for you're help
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