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Quadratic formula in C


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#1
Chris_027

Chris_027

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Hi I was wondering if anyone could help me out with a program I am trying to build. I'm new to the C language and am trying to learn as much as I can. My program solves the quadratic equation and I am trying to modify it with IF statements to make it capable of solving problems with complex solutions.
This is what I have so far.

# include <math.h>
# include <stdio.h>
# include <stdlib.h>

/*Function Prototypes */
double find_solution_1(double a, double b, double c);    /*Calculates 1st solution */
double find_solution_2(double, double, double);    /*Calculates 2nd solution */


int main(void)
{
    double a, b, c, s1, s2;
    
    printf("Enter the coefficient values for a, b, and c\n");   /*get input*/
    scanf("%lf" , &a);
    scanf("%lf" , &b);
    scanf("%lf" , &c);
    
    s1 = find_solution_1(a, b, c);                              /*function calls*/
    s2 = find_solution_2(a, b, c);
    printf("x = %.2f, x = %.2f\n" , s1, s2);                        /*display results*/
    
    
    
    system("pause");
    return (0);
}

double find_solution_1(double a, double b, double c)    /*Define Function */
{
       double  result;
       
       result = (-b + sqrt(b * b - 4 * a * c))/(2 * a);
       
       return (result);
}
double find_solution_2(double a, double b, double c)    /*Define Function */
{
       double  result;
       
       result = (-b - sqrt(b * b - 4 * a * c))/(2 * a);
       
       return (result);
}
Any help would be greatly appreciated.
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#2
MS-Free

MS-Free

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Great question. I hadn't really thought much about trying to program with complex numbers before...

If no naticve support is offered - your going to have to split your answers into 2 variables - a real part and an imaginary part.

Personally in regards to quadratics - I would create a function for calculating the value under the radical (sense that's where any imaginaries would come into play.

Perhaps also have a boolean variable isComplex.

Then, when isComplex = true, the final answer output may have to be a string.

solution = String.valueOf(Real) + String.valueOf(Imaginary)

I'm not going to go and give a specific answer in code sense I haven't learned C syntax yet.

Great programming exercise! Thanks for the challenge.

Hope that helps a little.
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