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# Nested 'IF' in Excel 2003

### #1 Gumby© Posted Today, 12:54 PM

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I'm trying to have a cell display a value based on the value in another cell using the following criteria:

IF B2 = a certain number then F2 = a number based on the criteria in the following formula, unfortunately I can't seen to get the formula to work and can't find the error I'm making. Any help would be greatly appreciated. Thanks in advance.

=IF (B2>1.6,-2,"NOT", IF (B2>1.3, B2<1.6),-1,"NOT", IF (B2>1.2, B2 < 1.6), 0,"NOT", IF (B2 >0.9, B2<1.19), 1,"NOT", IF B2< 0.9, 2,"NOT")

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### #2 zep516 Posted Today, 01:16 PM

zep516

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Hello Gumby,

Any help or ideas linked below.

IF function – nested formulas and avoiding pitfalls (microsoft.com)

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