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# Python even-odd sorting list

### #1 selfmade_android Posted 18 March 2012 - 08:20 PM

New Member

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• 1 posts
I need help with my program. I am getting a message that says: TypeError: unsupported operand type(s) for /: 'unicode' and 'int'
here is my program:
#Sorts a specified list of numbers into even and odd lists
ans = raw_input("Create a list of numbers seperated by commas to sort them into even and odd lists.")
ev = []
od = []
for i in [ans]:
if '.' in (i/2):
od.append(i)
else:
ev.append(i)
print("The even numbers are:")
print(ev)
print("The odd numbers are:")
print(od)
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### #2 risingphoenix1985 Posted 19 March 2012 - 03:39 PM

risingphoenix1985

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• 131 posts
Hello,

Just putting your code in the code tags to make it easier to read.

```#Sorts a specified list of numbers into even and odd lists
ans = raw_input("Create a list of numbers seperated by commas to sort them into even and odd lists.")
ev = []
od = []
for i in [ans]:
if '.' in (i/2):
od.append(i)
else:
ev.append(i)
print("The even numbers are:")
print(ev)
print("The odd numbers are:")
print(od)```

I wouldn't use the "/" symbol, Python modulus would do the trick here. You also have a problem with your types in that you are performing an int function on a list class which I don't believe are compatible.

You may want to consider type casting the user input to take int's or floats.
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### #3 risingphoenix1985 Posted 20 March 2012 - 05:57 PM

risingphoenix1985

Member

• Member
• 131 posts
Here is how I would have done it...

```s = (raw_input("please enter numbers separated by , "))
s1 = s.split(",")
even = []
odd = []
for i in s1:
num = long(i)
if num % 2 !=1:
even.append(int(num))
else:
odd.append(int(num))
print "even number set ...", even
print "odd number set...", odd```

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